Wednesday, November 6, 2013

Chemistry Unit 8 Final Project

Running Head: UNIT 8 Final reckon social unit 8 Final Project tammy Barker Kaplan University SC 155-01 Professor Leonard opulent 26, 2012 From what I see, technically, this is not a back-titration, because secondary ( gastric gastric antacid) is being added to acid, to a great extent invertebrate foot is added to the acid until the compare aim is reached. Wouldnt a back- titration involve going past the comparing point with storey and then back titrating with acid until equivalence was reached? Then, with each incident I am reacting the antacid and instauration with .040L (the 40mL) of 0.1M HCl, and groinearity quantify volume giving counterspyes as follows: (.040L HCl)*(0.1 counterspy HCl/L HCl) = .004 mol HCl. So in each case, in high society to farm to the equivalence point in this reaction of a unassailable acid with a st rong base, I contend to have .004 mol of base to estimabley react in a 1:1 ratio with the acid thats present. The combining of antacid and base that is added exit add up to .004 mol. 1. Since I am adding the antacid first, and then adding the same .
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05 M NaOH to pass away to equivalence, whichever antacid neutralizes the intimately base (ie- is the strongest) will require the least(prenominal) amount of tautologic base to reach equivalence. That would be the CVS brand, at .0199L (for simplicity, all volumes will be expressed in L, compensate though the chart is in mL). The weakes t would require the most spare base,! and that would be the Rennies, at .0244L. Worked out as follows: (.0199L NaOH)*(.05 mol NaOH/L NaOH) = .000995 mol NaOH .004 mol base required - .000995 mol from NaOH = .003005 mol base from CVS antacid (.0244L NaOH)*(.05 mol NaOH/L NaOH) = .00122 mol NaOH .004 mol base required - .00122 mol from NaOH = .002780 mol base from Rennies antacid All other volumes fall in the categories of among CVS and Rennies, so it good deal be confirmed that CVS is the strongest (most basic), and...If you want to get a full essay, order it on our website: BestEssayCheap.com

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